Final answer:
The power factor of a 6500 watt load connected to a 240 volt single-phase source drawing 33 amps is approximately 0.82, indicating the presence of reactive components in the load.
Step-by-step explanation:
To calculate the power factor of a load connected to a single-phase source, we use the formula:
Power Factor (PF) = Real Power (P) / Apparent Power (S), where Real Power is measured in watts (W) and Apparent Power is volts (V) multiplied by current (A).
In this case, the real power is given as 6500 W, and the apparent power can be calculated using the voltage and current supplied, which are 240 V and 33 A respectively.
Thus Apparent Power, S = Voltage (V) × Current (I)
= 240 V × 33 A
= 7920 VA (volt-amperes).
Now, we can calculate power factor as PF = 6500 W / 7920 VA.
Therefore, PF ≈ 0.8212.
This means that the power factor is approximately 0.82, which suggests that the load has some reactive components (inductive or capacitive) causing the current to be out of phase with the voltage.