Question

Assume that 2 bytes are used to store the color for each pixel on a display screen. How many kilobytes are required to store a display that uses 1024 columns and 768 rows of pixels? (round final answer to nearest whole number. In other words, the nearest kilobyte).

Answer 1

To store a display with 1024 columns and 768 rows, where each pixel requires 2 bytes for color information, 1,536 kilobytes of storage space is needed.

Step-by-step explanation:

To calculate the computer storage space required for a display that uses 1024 columns and 768 rows of pixels, where 2 bytes are used to store the color for each pixel, we can use the following steps:

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• Multiply the number of columns (1024) by the number of rows (768) to find the total number of pixels.
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• Multiply the total number of pixels by 2 bytes to find out how many bytes are used to store the display.
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• Divide the result by 1024 to convert from bytes to kilobytes (KB).

Here's the calculation:

1024 columns * 768 rows = 786,432 pixels

786,432 pixels * 2 bytes/pixel = 1,572,864 bytes

1,572,864 bytes / 1024 bytes/KB = 1,536 KB

Therefore, it would require 1,536 KB of storage space to store the display. This figure is already in whole kilobytes, so no rounding is necessary.

The basic unit of computer memory is the byte. One million bytes is known as a megabyte (MB).