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A woman deposits $7000 at the end of each year for 11 years in an account saving 3% interest compounded anually

(a) Find the final amount she will have on deposit.
(b) Her brother-in-law works in a bank that pays 2% compounded annually. If she deposits money in this back instead of the other one, how much wiil she have in her acoount?
(c) How mach would she lose over 11 years by using her brother-in-law's bank?

User R Day
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1 Answer

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Final answer:

The woman will have $9,979.33 on deposit in the original bank after 11 years. If she deposits money in her brother-in-law's bank instead, she will have $8,877.69. Therefore, she would lose $1,091.64 over 11 years by using her brother-in-law's bank.

Step-by-step explanation:

(a) To find the final amount she will have on deposit, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:

A is the final amount

P is the principal amount (amount deposited each year)

r is the annual interest rate (in decimal form)

n is the number of times interest is compounded per year

t is the number of years

Plugging in the values, we get:

A = 7000(1 + 0.03/1)^(1*11)

= 7000(1.03)^11

= 7000 * 1.4257619

= $9979.33

(b) To find the amount she will have if she deposits money in the bank paying 2% interest, we can use the same formula:

A = 7000(1 + 0.02/1)^(1*11)

= 7000(1.02)^11

= 7000 * 1.2682426

= $8877.69

(c) To find how much she would lose over 11 years by using her brother-in-law's bank, we can subtract the amount she would have in her brother-in-law's bank from the amount she would have in the original bank:

9979.33 - 8877.69 = $1091.64

User SentientBacon
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