Final answer:
There are 126 different ways to select the remaining 4 committee members from a pool of 9 people, after accounting for the president's position already being filled.
Step-by-step explanation:
In this mathematics problem, we're interested in determining the number of ways to select a committee of 5 people from a pool of 10, given that the president's position has already been filled by Jack. Since Jack's position reduces the pool of available candidates to 9, and we need to select 4 more committee members (totaling 5 with the president), we are looking for the number of combinations of 4 people from the remaining 9.
The formula for combinations (often denoted as C(n, k) or n choose k) where n is the total number of items to choose from, and k is the number of items to choose, is given by:
C(n, k) = n! / (k! * (n - k)!)
Plugging in our numbers, we get C(9, 4) which is equal to:
9! / (4! * (5!)) which simplifies to (9 * 8 * 7 * 6) / (4 * 3 * 2 * 1) which equals 126.
Therefore, there are 126 different ways to select the committee members.