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a 50-kg satellite circles planet cruton every 5.6 h in an orbit with a radius of 12 x 10⁶ m. what is the magnitude of the gravitational force on the satellite by planet cruton?

User Sfkleach
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1 Answer

2 votes

The magnitude of the gravitational force on the satellite by planet Cruton is 5.66 x 10^7 N.

Step-by-step explanation:

To calculate the magnitude of the gravitational force on the satellite by planet Cruton, we can use Newton's law of universal gravitation equation:

F = (G * m1 * m2) / r^2

where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between the centers of the two objects.

Plugging in the values, we have:

F = (6.67 x 10^-11 Nm^2/kg^2 * 50 kg * 5.97 x 10^24 kg) / (12 x 10^6 m)^2

Simplifying, we get:

F = 6.67 x 10^-11 Nm^2/kg^2 * 50 kg * 5.97 x 10^24 kg / (12 x 10^6 m)^2

F = 5.66 x 10^7 N

Therefore, the magnitude of the gravitational force on the satellite by planet Cruton is approximately 5.66 x 10^7 N.





The probable question can be: A 50 kg satellite circles "Cruton" every 5.6 h in an orbitwith a radius of 12x10^6 m. What is the magnitude of thegravitational force in N on the satellite by planet Cruton?

a. 63

b. 58

c. 68

d. 73

e. 50

User Markus
by
8.6k points
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