The magnitude of the gravitational force on the satellite by planet Cruton is 5.66 x 10^7 N.
Step-by-step explanation:
To calculate the magnitude of the gravitational force on the satellite by planet Cruton, we can use Newton's law of universal gravitation equation:
F = (G * m1 * m2) / r^2
where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between the centers of the two objects.
Plugging in the values, we have:
F = (6.67 x 10^-11 Nm^2/kg^2 * 50 kg * 5.97 x 10^24 kg) / (12 x 10^6 m)^2
Simplifying, we get:
F = 6.67 x 10^-11 Nm^2/kg^2 * 50 kg * 5.97 x 10^24 kg / (12 x 10^6 m)^2
F = 5.66 x 10^7 N
Therefore, the magnitude of the gravitational force on the satellite by planet Cruton is approximately 5.66 x 10^7 N.
The probable question can be: A 50 kg satellite circles "Cruton" every 5.6 h in an orbitwith a radius of 12x10^6 m. What is the magnitude of thegravitational force in N on the satellite by planet Cruton?
a. 63
b. 58
c. 68
d. 73
e. 50