Question

a chemist prepares a solution of iron(ii) bromide by measuring out 23 umol of iron(ii) bromide into a 150ml volumetric flask and filling the flask to the mark with water. calculate the concentration in of the chemist's iron(ii) bromide solution. round your answer to significant digits.

Answer 1

To find the concentration, convert 23 micromoles of iron(II) bromide to moles and the volume from mL to L, then divide moles by volume. The concentration is 1.53 × 10^-4 M.

Step-by-step explanation:

To calculate the concentration of the chemist's iron(II) bromide solution, we need to convert the amount of solute in micromoles to moles and divide by the volume of the solution in liters. We are given that 23 µmol of iron(II) bromide is measured into a 150 mL volumetric flask and filled with water.

First, convert micromoles to moles:

• 23 µmol = 23 × 10-6 mol

Next, convert the volume of water from mL to L:

• 150 mL = 0.150 L

Calculate the concentration in molarity (M), which is moles of solute per liter of solution:

• Concentration (M) = Moles of solute (mol) / Volume of solution (L)
• Concentration (M) = (23 × 10-6 mol) / 0.150 L
• Concentration (M) = 1.53 × 10-4 M

Thus, the concentration of the iron(II) bromide solution is 1.53 × 10-4 M.