Question

suppose we are using quadratic probing in a hash table that has a capacity of 93. how many values can be inserted and still guarantee finding a position to insert?

Answer 1

The number of values that can be inserted and still guarantee finding a position depends on the load factor. In this case, the maximum number of values that can be inserted is 46.

Step-by-step explanation:

In quadratic probing, when a collision occurs, the next available position in the hash table is found by incrementing the index by a quadratic function of the probe number.

In this case, the capacity of the hash table is 93. The number of values that can be inserted and still guarantee finding a position to insert depends on the load factor. The load factor is the ratio of the number of items stored in the hash table to the capacity of the hash table.

Let's assume the load factor is 0.5 (half the capacity of the hash table). Then, the maximum number of values that can be inserted and still guarantee finding a position to insert is half the capacity, which is 46.5. Since you cannot insert a fraction of a value, the maximum number of values that can be inserted is 46.

Keep in mind that this calculation assumes ideal circumstances and does not take into account other factors such as the distribution of the hash values or the specific implementation of the hash function.