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baseball team has a 24-man roster. how many different ways are there to choose a group of nine players to start the game?

User Qazimusab
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A 24-man baseball team boasts a mind-boggling 207,518,200 starting lineup options! Order doesn't matter, creating a combinatorial explosion of possibilities for managers to ponder before each game.

To calculate the number of starting lineups a baseball team with a 24-man roster can create, we use the concept of combinations without repetition. This means order doesn't matter, and each player is chosen only once.

Here's the formula:

Number of combinations = N! / (r! * (N-r)!)

where:

N is the total number of players (24)

r is the number of starting players (9)

Plugging in the values:

Number of combinations = 24! / (9! * 15!)

This calculation is quite large, but we can simplify it by utilizing the property of factorials:

Number of combinations = (24 * 23 * 22 * 21 * 20 * 19 * 18 * 17 * 16) / (9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1)

We can cancel out common factors in the numerator and denominator, making the calculation less daunting:

Number of combinations = (24 * 23 * 22 * 21 * 20 * 19 * 18 * 17) / (8 * 7 * 6 * 5 * 4 * 3 * 2)

Solving for the final answer:

Number of combinations = 207,518,200

Therefore, a baseball team with a 24-man roster has a whopping 207,518,200 different starting lineup possibilities!

User Ranjith King
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