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a heat engine perates between two reservoirs at 26.9 and 377. what is the mazimum efficiency possible ofr this engine?

User Myoshi
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The maximum theoretical efficiency of a heat engine operating between reservoir temperatures of 25°C and 300°C is approximately 47.99% after converting the given temperatures to kelvins and applying the Carnot efficiency formula.

Step-by-step explanation:

The student asks about the maximum efficiency for a heat engine that operates between two reservoirs at temperatures of 25°C and 300°C. To calculate the maximum efficiency, which is the Carnot efficiency, we need to convert these temperatures to kelvins. The formula for the Carnot efficiency is ì = 1 - (Tc/Th), where Tc is the cold reservoir temperature and Th is the hot reservoir temperature in kelvins.

First, we convert the given temperatures to kelvins:

The cold reservoir temperature (25°C) is Tc = 25 + 273.15 = 298.15 K.

The hot reservoir temperature (300°C) is Th = 300 + 273.15 = 573.15 K.

Using these temperatures, the maximum efficiency can be calculated:

ì = 1 - (Tc/Th) = 1 - (298.15/573.15) = 1 - 0.5201 = 0.4799 or 47.99%

Therefore, the maximum theoretical efficiency of the heat engine is approximately 47.99%.




The probable question can be: A heat engine operates between two reservoirs at temperatures of 25°C and 300°C. What is the maximum

eficiency for this engine?​

User Haven
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