163k views
0 votes
Write an equation for a line perpendicular to y=−5x+1 and passing through the point (−5,1) y=

1 Answer

1 vote

Final answer:

The equation of the line perpendicular to y = -5x + 1 and passing through the point (-5,1) is y - 1 = 1/5(x + 5).

Step-by-step explanation:

To find the equation of a line perpendicular to y = -5x + 1 and passing through the point (-5,1), we need to determine the slope of the new line first. The slope of a line perpendicular to another line is the negative reciprocal of the original slope.

The original slope is -5, so the slope of the new line is 1/5. Now, we can use the point-slope form of a line to write the equation of the line. Substitute the slope and the coordinates of the point into the equation:

y - y1 = m(x - x1)

where (x1, y1) is the point and m is the slope. Plugging in the values, we get:

y - 1 = 1/5(x + 5)

This is the equation of the line perpendicular to y = -5x + 1 and passing through the point (-5,1).

User Jellisa
by
7.8k points