163k views
0 votes
Write an equation for a line perpendicular to y=−5x+1 and passing through the point (−5,1) y=

1 Answer

1 vote

Final answer:

The equation of the line perpendicular to y = -5x + 1 and passing through the point (-5,1) is y - 1 = 1/5(x + 5).

Step-by-step explanation:

To find the equation of a line perpendicular to y = -5x + 1 and passing through the point (-5,1), we need to determine the slope of the new line first. The slope of a line perpendicular to another line is the negative reciprocal of the original slope.

The original slope is -5, so the slope of the new line is 1/5. Now, we can use the point-slope form of a line to write the equation of the line. Substitute the slope and the coordinates of the point into the equation:

y - y1 = m(x - x1)

where (x1, y1) is the point and m is the slope. Plugging in the values, we get:

y - 1 = 1/5(x + 5)

This is the equation of the line perpendicular to y = -5x + 1 and passing through the point (-5,1).

User Jellisa
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories