Final answer:
The probability that another person from the suspect's group has the same genotype a1a2b2c1c2, given allele frequencies of a1=0.9, b1=0.99, and c1=0.8, is 0.72%.
Step-by-step explanation:
The question pertains to the subject of genetics within Biology, a branch of science that deals with the inheritance of traits in organisms. Using principles of genetic probability, we determine the likelihood that another person in a suspect's population group would have the same combination of alleles as those found in the DNA evidence from a crime scene. The given allele frequencies for a1, b1, and c1 are 0.9, 0.99, and 0.8, respectively. To compute the probability of another person having the same genotype a1a2b2c1c2, we need to consider the probability of each allele being passed on independently.
Since the individual has alleles a1, b2, and c1, we need to calculate the probability of selecting these alleles from the population gene pool. The probability of another individual having the same genotype would be the product of the probabilities of each independent allele being selected. Therefore, we multiply the corresponding allele frequencies for a1 (0.9), (1 - frequency of b1, as we need the frequency of b2 which is not given, so it would be 1 - 0.99 = 0.01), and c1 (0.8). The resulting probability would be:
Probability = 0.9 (for a1) * 0.01 (for b2) * 0.8 (for c1) = 0.0072
The probability that another person in the population group has the exact same allele pattern is 0.72%.