When two eagles fly directly toward each other, the second eagle receives a frequency of 2955 Hz.
Step-by-step explanation:
When two eagles fly directly toward each other, their relative velocity is the sum of their individual velocities. In this case, the relative velocity is (19.8 m/s + 14.6 m/s) = 34.4 m/s.
The Doppler effect formula for frequency is given by:
f' = f(v + vd) / (v - vs)
Where f' is the observed frequency, f is the emitted frequency, v is the speed of sound, vd is the velocity of the detector, and vs is the velocity of the source.
Plugging in the given values, we get:
f' = 2609 Hz * (340 m/s + 14.6 m/s) / (340 m/s - 19.8 m/s) = 2955 Hz
Therefore, the second eagle receives a frequency of 2955 Hz.