Question

Calculate the enthalpy of formation of 1 mole SO₂(g) from the standard enthalpy changes of the following reactions:

2SO₃​(g)→2SO₂​(g)+O₂​(g)

ΔH°rxn 1 = +196 kJ

Answer 1

To find the enthalpy change when 58.0 g of SO2 is reacted with excess oxygen, calculate the moles of SO2, then multiply by the conversion factor of enthalpy change per mole.

Step-by-step explanation:

To calculate the enthalpy change for the reaction of 58.0 g of sulfur dioxide (SO2) with excess oxygen, follow these steps:

• First, calculate the moles of SO2:
  Mass of SO2 = 58.0 g
  Molar mass of SO2 = 64.07 g/mol
  
  Moles of SO2 = Mass of SO2 / Molar mass of SO2
• Then, use the provided enthalpy ratio:
  ΔH = -198 kJ for the reaction of 2 mol SO2
• Multiply the moles of SO2 by the conversion factor of -198 kJ per 2 mol of SO2 to find the enthalpy change for the reaction.