Question

an automobile tire is filled to an absolute pressure of 3.0 ATM at a temperature of 30 degree C. later it is driven to a place where the temperature is only -20 degree C. What is the absolute pressure of the tire at the cold place? (assume that the air behaves as an ideal gas.)

Answer 1

The absolute pressure of the tire at the cold place is 2.52 ATM. The new absolute pressure of the tire after a decrease in temperature can be determined by using Gay-Lussac's Law of P1/T1 = P2/T2, where P represents pressure and T represents temperature in Kelvin.

Step-by-step explanation:

According to the ideal gas law, the pressure of a gas is directly proportional to its temperature. When the temperature decreases, the pressure of the gas decreases as well.

In this case, the initial temperature of the tire is 30 degrees C, and the final temperature is -20 degrees C.

Convert the temperature to Kelvin: Initial temperature = 30 + 273

= 303 K,

temperature = -20 + 273

= 253 K

Use the ideal gas law equation: P1/T1 = P2/T2

Substitute the values into the equation and solve for P2:

(3.0 ATM)/(303 K)

= P2/(253 K)

Cross-multiply and calculate P2:

P2 = (3.0 ATM) * (253 K) / (303 K) =

2.52 ATM

Therefore, the absolute pressure of the tire at the cold place is 2.52 ATM.