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If a pendulum-driven clock gains 7.35 s/day, what fractional change in pendulum length must be made for it to keep perfect time? Express your answer as a percentage change; keep sufficient significant figures. Note: this problem may seem a little intimidating, but you can do it! Read both of the hints carefully, and think about what quantities are changing and which are not. dl/l =

User Khtad
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The fractional change in pendulum length required to keep perfect time is approximately 0.004254%. This means the pendulum needs to be lengthened by about 0.004254% to achieve the desired period adjustment.


To solve this problem, we'll use the following steps:

Determine the necessary period change:

The clock gains 7.35 seconds per day, which means its period is shorter than it should be.

A day has 86400 seconds, so the clock's period needs to increase by 7.35 seconds / 86400 seconds = 0.00008507575%.

Relate period change to length change:

The period of a pendulum is directly proportional to the square root of its length.

Mathematically, this relationship can be expressed as: T ∝ √L, where T is the period and L is the length.

To achieve the necessary period change, we need to adjust the length accordingly.

Calculate the fractional change in length:

Since T ∝ √L, we can write: (T + ΔT) / T = √(L + ΔL) / √L, where ΔT and ΔL represent the changes in period and length, respectively.

Squaring both sides and simplifying, we get: (ΔL / L) = [(1 + ΔT / T)^2 - 1]

Plugging in the values for ΔT / T (0.00008507575) and solving, we find: ΔL / L ≈ 0.00004254 * 100% = 0.004254%.

Therefore, the fractional change in pendulum length required to keep perfect time is approximately 0.004254%. This means the pendulum needs to be lengthened by about 0.004254% to achieve the desired period adjustment.

The probable question is in the image attached.

If a pendulum-driven clock gains 7.35 s/day, what fractional change in pendulum length-example-1
User Billy Moon
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