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On Christmas Day my parents bought 16 toys for my three siblings the oldest got 1/2 of the toys and another got 1/4 while the youngest got 1/2 how many toys did each of them get

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Final answer:

The question contains a mathematical error as it implies both the oldest and youngest siblings received half of the toys, which is impossible. The oldest sibling got 8 toys, and the second sibling got 4 toys. Assuming the youngest receives the remainder, they also get 4 toys.

Step-by-step explanation:

The subject of this question is Mathematics, specifically dealing with fractions and the division of quantities. Since we have a total of 16 toys to be divided among three siblings, we use fractions to determine how many toys each sibling got. The first step is to calculate the number of toys the oldest sibling received.

According to the question, the oldest sibling got 1/2 of the toys. To find out how many toys this is, we multiply the total number of toys, which is 16, by 1/2:

16 toys × 1/2 = 8 toys

Next, the other sibling is said to have received 1/4 of the toys. Again, we multiply the total number of toys by 1/4:

16 toys × 1/4 = 4 toys

However, there seems to be an error in the way the question is phrased, since it indicates the youngest also got 1/2 of the toys. Since the oldest sibling already got 1/2, and another sibling got 1/4; there can't be 1/2 left for the youngest sibling. If we were to proceed assuming the youngest got the remaining toys:

Remaining toys = Total toys - Toys for oldest - Toys for another sibling

Remaining toys = 16 toys - 8 toys - 4 toys = 4 toys

In conclusion, if we distribute the toys based on the fractions provided, the oldest sibling would receive 8 toys, another sibling would receive 4 toys, and due to the error in the original problem assumption, we'd say the youngest sibling gets the remaining 4 toys, if we correct the youngest's fraction to whatever is left which in this case is 4 out of 16 or 1/4.

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Final answer:

According to the information provided, there is a mistake as the fractions given for toy distribution exceed the whole. Assuming the youngest is to receive the remaining toys after the oldest and another sibling have received theirs, the oldest would get 8 toys, the second sibling 4 toys, and the youngest also 4 toys.

Step-by-step explanation:

The question involves basic fraction and division concepts to determine how many toys each sibling received based on the proportion given. If there are 16 toys and the distribution is such that the oldest sibling got 1/2 of the toys, one sibling got 1/4, and the youngest got 1/2, there seems to be an error as the fractions add up to more than the whole, which is not possible in this context. However, if we proceed with the assumption that the last fraction is incorrect and we're meant to divide the remainder equally, this is how you would calculate it:

• The oldest sibling gets 1/2 of 16 toys, which is 16 * 1/2 = 8 toys.

• Another sibling gets 1/4 of 16 toys, which is 16 * 1/4 = 4 toys.

• To find out how many toys the youngest gets, we subtract the amount the first two siblings got from the total. So, 16 - (8+4) = 16 - 12 = 4 toys.

Therefore, the oldest sibling got 8 toys, another sibling got 4 toys, and the youngest also received 4 toys.