Final answer:
To find the linear map T:R²→R² that takes (1,2) to (2,3) and (0,1) to (1,4), we express T as a 2x2 matrix. By solving the corresponding matrix equations, we find the matrix A = [[0, 1], [-5, 4]], which gives us the linear map T((x, y)) = (y, -5x + 4y).
Step-by-step explanation:
To find a linear map T:R²→R² such that T((1,2))=(2,3) and T((0,1))=(1,4), we can assume that the linear map T can be represented by a 2x2 matrix A = [[a, b], [c, d]]. The action of T on a vector (x, y) in R² is represented as a matrix-vector multiplication A*(x, y), resulting in a new vector in R².
Using the given mappings, we have two matrix equations:
A*(1, 2) = (2, 3)
- The first equation corresponds to the system:
a*1 + b*2 = 2
a + 2b = 2
- From the second equation, we get:
a*0 + b*1 = 1
b = 1
- Substituting b and d back into the first system:
a + 2*1 = 2 → a = 0
- Thus, the matrix A representing the linear map T is:
A = [[0, 1], [-5, 4]]
This gives us the linear map T as follows:
T((x, y)) = (0*x + 1*y, -5*x + 4*y)