62.7k views
0 votes
Let y=ax³ where a=7 then y′′ at x=3 is equal to

1 Answer

2 votes

Final answer:

To find the second derivative of y=ax³, differentiate y'=3ax² with respect to x, substitute a=7 into the second derivative, and evaluate y'' at x=3. The value of y'' at x=3 is 126.

Step-by-step explanation:

To find the second derivative of y=ax³, we first need to find the first derivative of y. The first derivative of y=ax³ is y'=3ax². Now, to find the second derivative, we differentiate y'=3ax² with respect to x. Differentiating 3ax² gives us y''=6ax.

Given that a=7, we substitute a=7 into y''=6ax to find y''=6(7)x=42x.

Now we can find y'' at x=3 by substituting x=3 into y''=42x. Therefore, y'' at x=3 is 42(3)=126.

User Giorgiline
by
7.7k points