Question

Consider the following method.

/** Precondition: p > 0
*/
public static int method0202(int p)
{
int count = 1;
for (int q = 1; q < p; q++)
count += count;
return count;
}
What value is returned as a result of the fall method0202(5) ?

a. 5
b. 16
c. 15
d. 7
e. 8

Answer 1

The method method0202(5) doubles the count variable four times, starting from 1 and resulting in a value of 16 when returned.

Step-by-step explanation:

When using the method method0202(5), it initially sets count to 1. Then, for every integer q starting from 1 and incrementing by 1 up to but not including p (which is 5), it doubles the count. The for-loop runs four times (q = 1, 2, 3, 4), so count doubles four times: 1 (initial), 2, 4, 8, 16. Therefore, when the loop is finished, and count is returned, the value will be 16.