Question

How many grams of CO2 can be produced from 150 grams of O2?

C3H8 + 5 02
->
3 CO2 + 4H2O

Answer 1

120 g CO₂

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Atomic Structure

• Reading a Periodic Table

Stoichiometry

• Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

[RxN - Balanced] C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

[Given] 150 g O₂

Step 2: Identify Conversions

[RxN] 5 mol O₂ → 3 mol CO₂

[PT] Molar Mass of O - 16.00 g/mol

[PT] Molar Mass of C - 12.01 g/mol

Molar Mass of O₂ - 2(16.00) = 32.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

Step 3: Stoich

1. [DA] Set up:
   `\displaystyle 150 \ g \ O_2((1 \ mol \ O_2)/(32.00 \ g \ O_2))((3 \ mol \ CO_2)/(5 \ mol \ O_2))((44.01 \ g \ CO_2)/(1 \ mol \ CO_2))`
2. [DA] Multiply/Divide [Cancel out units]:
   `\displaystyle 123.778 \ g \ CO_2`

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

123.778 g CO₂ ≈ 120 g CO₂