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Calculate the concentration of CO₂ (in M) in a soft drink after the bottle is opened and the solution equilibrates at 25°C under a CO₂ partial pressure of 3.0 x 10⁻⁴ atm. The Henry's Law constant for CO₂ in water at this temperature is 0.034 mol/L- atm.

a. 8.8 x 10⁻³
b. 1.1
c. 110
d. 1.0 x 10⁻⁵
e. 1.0 x 10⁻³

1 Answer

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Final answer:

Using Henry's Law and the given constants, the concentration of CO₂ in a soft drink equilibrating at 25°C under a partial pressure of 3.0 x 10⁻⁴ atm is calculated to be 1.0 x 10⁻⁵ M.The mentioned correct option in the final answer is 1.0 x 10⁻⁵ M.

Step-by-step explanation:

To calculate the concentration of CO₂ in a soft drink after the bottle is opened and the solution equilibrates at 25°C under a CO₂ partial pressure of 3.0 x 10⁻⁴ atm, we apply Henry's Law, which states:

C = kP

Where:

  • C is the concentration of the gas (mol/L),
  • k is the Henry's Law constant (mol/L-atm), and
  • P is the partial pressure of the gas (atm).

Given the Henry's Law constant for CO₂ in water at 25°C is 0.034 mol/L-atm, and the partial pressure of CO₂ is 3.0 x 10⁻⁴ atm, the concentration can be calculated as follows:

C = (0.034 mol/L-atm)(3.0 x 10⁻⁴ atm) = 1.02 x 10⁻⁵ mol/L

Therefore, the concentration of CO₂ in the soft drink under these conditions is 1.0 x 10⁻⁵ M, which corresponds to the option d.

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