87.2k views
2 votes
Find all the values of x such that the given series would converge. (8x - 6)" n?

1 Answer

6 votes

Final answer:

To find the values of x for which the series converges, we apply the convergence criterion for geometric series to the given expression (8x - 6)^n, resulting in an interval (5/8, 7/8) for x.

Step-by-step explanation:

The question is asking to determine the range of values for x that would make the series converge. The series provided, (8x - 6)^n, is a geometric series where the common ratio is (8x - 6). For a geometric series to converge, the common ratio must have an absolute value less than 1. The condition for convergence can be written as:

|8x - 6| < 1

Solving for x gives us two inequalities:

  1. 8x - 6 < 1
  2. -(8x - 6) < 1

From the first inequality, solving for x yields:

8x < 7

x < 7/8

From the second inequality, we get:

8x - 6 > -1

8x > 5

x > 5/8

Therefore, for the series to converge, x must be in the interval (5/8, 7/8).

User Vladimir Tolstikov
by
8.3k points