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A line passes through the point (-8, 4) and has a slope of -2. Write an equation in slope-intercept form for this line. D=0 음. 믐 Х 5 ?

User Lynne
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Final answer:

The equation of the line passing through the point (-8, 4) with a slope of -2 is y = -2x - 12. This is the slope-intercept form of the line, where -2 is the slope and -12 is the y-intercept.

Step-by-step explanation:

To write the equation of the line that passes through the point (-8, 4) with a slope of -2, you can use the point-slope form of a line's equation, which is y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope.

For this line:



Substituting these values into the equation, we get:

y - 4 = -2(x - (-8))

Simplify the equation by distributing the slope and moving the y-intercept to the other side:

y - 4 = -2x - 16

Add 4 to both sides to get the slope-intercept form, which is y = mx + b:

y = -2x - 12

This is the equation of the line in slope-intercept form where the y-intercept is -12.

User Ddonche
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