Final answer:
The number of one bits in the binary expansion of 2 to the power of 29 minus 2 to the power of 11 is 18. The binary representation of 2^29 has a 1 followed by 29 zeros, and 2^11 has a 1 followed by 11 zeros. The subtraction results in 18 consecutive one bits from the 29th down to the 12th position.
Step-by-step explanation:
The question asks about the number of one bits in the binary expansion of 229 - 211. In binary, 229 is represented as a 1 followed by twenty-nine 0s. Similarly, 211 is a 1 followed by eleven 0s. When we perform the subtraction, all bits from the 29th position down to the 12th position will be one bits because the 1 in the twelfth position from 211 will be subtracted from a 0 in 229, resulting in all 1's in those positions.
Therefore, there will be 29 - 11 = 18 one bits representing the difference 229 - 211.