Question

An RL. circuit with a 1−Ω resistor and a 0,01−H inductor carries a current of 1 A at t=0, at which time a voltage source E(t) =cos(30π)vis added. Deternine the subsequent inductor current and voltage. l(t)=?

Answer 1

In an RL circuit with a 1-Ω resistor and 0.01-H inductor, the subsequent inductor current can be found using I(t) = (1 - e^(-Rt/L)). The voltage across the inductor can be calculated using Ohm's law, V(t) = IR.

Step-by-step explanation:

In an RL circuit with a 1-Ω resistor and a 0.01-H inductor, a current of 1 A flows initially when a voltage source of E(t) = cos(30π)t is added. To determine the subsequent inductor current and voltage, we can use the equation I(t) = (1 - e^(-Rt/L)).

Plugging in the values of R = 1 Ω, L = 0.01 H, and t = 0, we find the initial inductor current I(0) = 1 A. To find the voltage across the inductor, we can use Ohm's law, V(t) = IR, where I is the inductor current and R is the resistor value.

Therefore, the subsequent inductor current is I(t) = 1 - e^(-t/0.01), and the voltage across the inductor is V(t) = (1 - e^(-t/0.01)) * 1 Ω.