Question

A sample of an ideal gas goes through the process shown in Figure . From A to B, the process is adiabatic; from B to C, it is isobaric with 345 kJ of energy entering the system by heat; from C to D, the process is isothermal; and from D to A, it is isobaric with 371 kJ of energy leaving the system by heat. Determine the difference in internal energy E int,B −E int.A

Answer 1

The difference in internal energy (Eint,B - Eint.A) is 371 kJ.

Step-by-step explanation:

From point A to point B, the process is adiabatic, which means that no heat is exchanged with the surroundings. Adiabatic processes are characterized by a decrease in temperature due to the work done by the gas. The change in internal energy (Eint,B - Eint.A) can be calculated using the first law of thermodynamics:

Eint,B - Eint,A = Q - W

Since there is no heat exchange, Q=0. And since the process from A to B is adiabatic, the work done is negative. Therefore,

Eint,B - Eint,A = 0 - (-371) kJ = 371 kJ