Final answer:
The size of a multi-level indexed file with a block size of 4K, four direct links, and two 1st level indirect links is calculated as 4 blocks from direct links and 2048 blocks from indirect links, totaling 8404992 bytes.
Step-by-step explanation:
The size of a multi-level indexed file can be calculated by adding the storage space pointed to by the direct and indirect links. Given a block size of 4K (4096 bytes) and a block address size of 4 bytes, we can determine the file size as follows:
- 4 direct links point to 4 blocks of size 4096 bytes each.
- Each 1st level indirect link can point to 4096 / 4 = 1024 blocks. So, 2 first-level indirect links can point to a total of 2 * 1024 = 2048 blocks.
To compute the total file size, the size of the blocks pointed to by both direct and indirect links need to be summed up:
- Size contributed by direct links: 4 * 4096 bytes = 16384 bytes
- Size contributed by 1st level indirect links: 2048 * 4096 bytes = 8388608 bytes
The total file size is 16384 bytes + 8388608 bytes = 8404992 bytes.