The second-order maximum for light with a wavelength of 690 nm in the double-slit experiment will be located approximately 25,860 nm away from the central bright spot on the screen.
To determine the location of the second-order maximum for light of wavelength 690 nm in the double-slit experiment, we can use the formula:
y = (m * λ * L) / d
where:
y is the distance from the central bright spot to the location of the maximum,
m is the order of the maximum,
λ is the wavelength of the light,
L is the distance from the slits to the screen, and
d is the distance between the slits.
Given:
For the third-order maximum, m = 3, λ = 490 nm, L = 1.9 m, and d = 10 mm = 0.01 m.
Using these values, we can calculate the distance for the third-order maximum:
y₃ = (3 * 490 nm * 1.9 m) / 0.01 m
= 28410 nm
Now, we can calculate the distance for the second-order maximum using the same formula, but with the new wavelength of 690 nm:
y₂ = (2 * 690 nm * 1.9 m) / 0.01 m
= 25860 nm
Therefore, the second-order maximum for light of wavelength 690 nm will be located approximately 25,860 nm away from the central bright spot on the screen.