Question

in a double-slit experiment, the third-order maximum for light of wavelength 490 nm is located 10 mm from the central bright spot on a screen 1.9 m from the slits. light of wavelength 690 nm is then projected through the same slits.How far from the central bright spot will the second-order maximum of this light be located?

Answer 1

The second-order maximum for light with a wavelength of 690 nm in the double-slit experiment will be located approximately 25,860 nm away from the central bright spot on the screen.

To determine the location of the second-order maximum for light of wavelength 690 nm in the double-slit experiment, we can use the formula:

y = (m * λ * L) / d

where:

y is the distance from the central bright spot to the location of the maximum,

m is the order of the maximum,

λ is the wavelength of the light,

L is the distance from the slits to the screen, and

d is the distance between the slits.

Given:

For the third-order maximum, m = 3, λ = 490 nm, L = 1.9 m, and d = 10 mm = 0.01 m.

Using these values, we can calculate the distance for the third-order maximum:

y₃ = (3 * 490 nm * 1.9 m) / 0.01 m

= 28410 nm

Now, we can calculate the distance for the second-order maximum using the same formula, but with the new wavelength of 690 nm:

y₂ = (2 * 690 nm * 1.9 m) / 0.01 m

= 25860 nm

Therefore, the second-order maximum for light of wavelength 690 nm will be located approximately 25,860 nm away from the central bright spot on the screen.