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Determine if the following functions are one-to-one and map onto their indicated codomains. Is the function a bijection? Prove your answers.

(a) f : R => (-1, 1), f(x) = cos(x).
(b) The greatest integer function, int : R => Z.
(c) f : R => R

F(x) = { 2-x if x<1
1/x if x > 1

User Anpatel
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Final answer:

The cosine function is not one-to-one across its domain and not a bijection. The greatest integer function is also not one-to-one and not a bijection. The piecewise function is not one-to-one due to the discontinuity at x = 1, and therefore not a bijection.

Step-by-step explanation:

To determine if the given functions are one-to-one and map onto their indicated codomains and thus check if they are bijections, we apply the definitions and perform the necessary tests for each function.

Function a: f(x) = cos(x)

The cosine function is not one-to-one on the entire real line because it repeats values in each period of 2π. For example, cos(0) = cos(2π) = 1. Since it fails the horizontal line test, it cannot be a bijection. Although it maps to the interval (-1, 1), it does not cover every value exactly once.

Function b: Greatest Integer Function int : R ⇒ Z

The greatest integer function, also known as the floor function, is not one-to-one because multiple real numbers can map to the same integer. For instance, int(1.5) = int(1.9) = 1. However, it maps onto Z because every integer has a corresponding real-number pre-image. It is also not a bijection.

Function c: Piecewise Function

For the piecewise function, we consider each segment individually:

2 - x for x < 1: This segment is a line with a negative slope and is one-to-one.

1/x for x > 1: This segment is a hyperbola and is also one-to-one.

However, combining these two segments does not provide a one-to-one mapping across the entire domain of real numbers due to the discontinuity at x = 1, hence not a bijection.

User Keba
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