Final answer:
The mass of water that can be produced when paraffin burns in oxygen is 662.75 grams.
Step-by-step explanation:
To determine the mass of water that can be produced when paraffin burns in oxygen, we need to use stoichiometry. The balanced equation for the combustion of paraffin is:
2C₂₅H₅₂ + 71O₂ ⟶ 50CO₂ + 52H₂O
From the equation, we can see that for every 52 moles of water produced, 2 moles of paraffin are consumed. And since we have 500.00 grams of paraffin, which has a molar mass of 353.26 g/mol, we can calculate the moles of paraffin:
moles of paraffin = mass of paraffin / molar mass of paraffin = 500.00 g / 353.26 g/mol = 1.415 mol
Now, using the mole ratio from the balanced equation, we can calculate the moles of water produced:
moles of water = moles of paraffin x (52 moles H₂O / 2 moles paraffin) = 1.415 mol x (52 / 2) = 36.78 mol
Finally, we can convert the moles of water to grams:
mass of water = moles of water x molar mass of water = 36.78 mol x 18.02 g/mol = 662.75 g