Question

suppose that the following code executes in main: mov ebx, 4 mov edx, 5 quiz2 ebx, edx upon completion, ebx will contain (decimal).

Answer 1

The code is an assembly language snippet assigning values to registers. The 'quiz2' instruction is not recognized in x86 assembly, so EBX should remain with its assigned value of 4 after code execution.

Step-by-step explanation:

The question involves the analysis of an assembly language code snippet. Assembly language is a low-level programming language used to interface with computer hardware directly. The specific instruction set being referenced appears to be x86 assembly, which is commonly used in programming for Intel and AMD processors.

The code in question is executing two move instructions:

• mov ebx, 4 - This instruction places the decimal value 4 into the EBX register.
• mov edx, 5 - This instruction places the decimal value 5 into the EDX register.

The quiz2 instruction is not standard and appears to be a placeholder or typo. In standard x86 assembly, this instruction would not be recognized. Since quiz2 is not a valid instruction, the value in EBX remains 4 after the execution of the provided code.