122k views
2 votes
Some dice are specially designed so that 1 comes up a fifth of the time, 6 never comes up, and all the other outcomes are equally likely.

Find the probabilities of all the possible outcomes. (Enter your probabilities as fractions.)

Outcome 1 2 3 4 5 6
Probability

Find the probability that an odd number faces up. they

1 Answer

5 votes

Final answer:

The probabilities of the outcomes on the specially designed die are 1/5 each for outcomes 1, 2, 3, 4, and 5, and 0 for outcome 6. The probability of rolling an odd number (1, 3, or 5) is therefore 3/5.

Step-by-step explanation:

In a specially designed die where outcome 1 comes up a fifth of the time, outcome 6 never comes up, and the remaining outcomes (2, 3, 4, 5) are equally likely, we need to calculate the probabilities of all the possible outcomes.

The probability for outcome 1 is already given as 1/5. Since the die does not land on 6 at all, the probability for outcome 6 is 0. For the other outcomes (2, 3, 4, 5), we have a remaining probability of 4/5 (1 - 1/5), which needs to be equally distributed among the four numbers. Since there are four equally probable outcomes left, we divide 4/5 by 4, resulting in a probability of 1/5 for each one.

Therefore, the probabilities for the outcomes are:

  • Probability of 1 = 1/5
  • Probability of 2 = 1/5
  • Probability of 3 = 1/5
  • Probability of 4 = 1/5
  • Probability of 5 = 1/5
  • Probability of 6 = 0

For the probability of rolling an odd number (1, 3, or 5), we simply add their probabilities:

Probability of an odd number = Probability of 1 + Probability of 3 + Probability of 5

= 1/5 + 1/5 + 1/5 = 3/5

User Yoyoyoyosef
by
9.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories