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How to get the density of this unknown liquid?

How to get the density of this unknown liquid?-example-1
User Tyson
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2 Answers

10 votes

Answer:

Measure the volume of water poured into a graduated cylinder, then place the object in the water and remeasure the volume. The difference between the two volume measurements is the volume of the object. Now simply divide the mass by the volume to calculate the density of the object.

User Faur
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The density of the unknown liquid is approximately
\(2588.16 \, \text{g/L}\) when 25.00 mL is transferred into the flask.

To find the density of the unknown liquid, we can use the formula:


\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]

The mass of the liquid is the difference between the mass of the flask plus the liquid and the mass of the empty flask:


\[ \text{Mass of liquid} = \text{Mass of flask + liquid} - \text{Mass of empty flask} \]


\[ \text{Mass of liquid} = 143.246 \, \text{g} - 78.542 \, \text{g} \]


\[ \text{Mass of liquid} = 64.704 \, \text{g} \]

The volume of the liquid is given as 25.00 mL. However, it's crucial to convert this volume to liters for consistency in units. There are 1000 milliliters in a liter, so:


\[ \text{Volume of liquid} = 25.00 \, \text{mL} * (1)/(1000) \, \text{L/mL} \]


\[ \text{Volume of liquid} = 0.025 \, \text{L} \]

Now, apply the formula for density:


\[ \text{Density} = \frac{\text{Mass of liquid}}{\text{Volume of liquid}} \]


\[ \text{Density} = \frac{64.704 \, \text{g}}{0.025 \, \text{L}} \]


\[ \text{Density} \approx 2588.16 \, \text{g/L} \]

Therefore, the density of the unknown liquid is approximately
\(2588.16 \, \text{g/L}\).

The question probable maybe:

A student finds the mass of an empty flask to be 78.542 grams. She carefully transfers 25.00 mL of an unknown liquid into the flask and the mass of the flask plus the liquid together is 143.246 grams. What is the density of this unknown liquid?

User Krishna Sunuwar
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