Question

A room of volume V contains air having equivalent molar mass M (in g/mol). If the temperature of the room is raised from T1 to T2, what mass of air will leave the room? Assume that the air pressure in the room is maintained at P0

Answer 1

To find the mass of air that will leave the room when the temperature is raised from T1 to T2, we can use the ideal gas law and the molar mass of air. First, calculate the number of moles of air in the room at temperature T1 and T2. Then, subtract the number of moles at T2 from T1 and multiply by the molar mass of air to find the mass of air that leaves the room.

Step-by-step explanation:

The question asks for the mass of air that will leave the room when the temperature is raised from T1 to T2. To solve this, we can use the ideal gas law, which is PV = nRT. Rearranging the equation, we get n = PV / RT, where n is the number of moles of gas.

First, we need to calculate the number of moles of air in the room at temperature T1. Plug in the values of volume V, molar mass M, and temperature T1 into the equation.

n1 = (P0V / RT1) * M

Next, calculate the number of moles of air in the room at temperature T2. Plug in the values of volume V, molar mass M, and temperature T2 into the equation.

n2 = (P0V / RT2) * M

The mass of air that leaves the room can be calculated by subtracting n2 from n1 and then multiplying by the molar mass of air. The mass of air leaving the room is given by:

Mass of air = (n1 - n2) * M

Remember to convert temperature from Celsius to Kelvin by adding 273.15.