Final answer:
The balanaced equation is 4IO₃⁻ (aq) + Re (s) + 10OH⁻ (aq) -> 4ReO₄⁻ (aq) + 26H₂O (l)
To balance the redox reaction in basic solution, follow the steps for balancing redox reactions in basic media.
Step-by-step explanation:
To balance the redox reaction in basic solution, we can follow the steps for balancing redox reactions in basic media.
1. Write the balanced half-reactions for the oxidation and reduction processes:
Oxidation: IO₃⁻ (aq) -> ReO₄⁻ (aq) + 6H₂O (l) + 6e⁻
Reduction: Re (s) + 4OH⁻ (aq) -> ReO₄⁻ (aq) + 2H₂O (l) + 4e⁻
2. Balance the number of electrons transferred between the two half-reactions by multiplying the oxidation half-reaction by 4.
Oxidation: 4IO₃⁻ (aq) -> 4ReO₄⁻ (aq) + 24H₂O (l) + 24e⁻
Reduction: Re (s) + 4OH⁻ (aq) -> ReO₄⁻ (aq) + 2H₂O (l) + 4e⁻
3. Add the two half-reactions together:
4IO₃⁻ (aq) + Re (s) + 4OH⁻ (aq) -> 4ReO₄⁻ (aq) + 26H₂O (l)
4. Balance the charge by adding OH⁻ ions to both sides of the equation:
4IO₃⁻ (aq) + Re (s) + 10OH⁻ (aq) -> 4ReO₄⁻ (aq) + 26H₂O (l)
This balanced redox reaction occurs in basic solution.