Final answer:
To place the values 9, 34, 49, 16, 32, and 51 into an array of size 17 using linear probing, you compute the hash for each value and insert it into the array; if the index is taken, proceed to the next open index.
Step-by-step explanation:
The question involves writing a program to define an array and populate it using a method called linear probing. Linear probing is a collision resolution technique in hash tables, where if a hash function leads to a collision (two values hashing to the same array index), it searches linearly for the next empty slot in the array to place the value.
To place the values 9, 34, 49, 16, 32, and 51 into an array of size 17 using linear probing, you would start by calculating the hash for each value. This could involve using a simple modulus operation, for example, hash = value % array_size. Once you have the hash, you insert the value into the array at that index. If the index is already occupied, you move to the next index in the array, wrapping around to the beginning if necessary.
Here is a pseudocode example:
array_size = 17
hash_array = [None] * array_size
values_to_insert = [9, 34, 49, 16, 32, 51]
for value in values_to_insert:
index = value % array_size
while hash_array[index] is not None:
index = (index + 1) % array_size
hash_array[index] = value
In this example, 'None' represents an empty slot in the array. The while loop continues until it finds an empty slot where it can insert the value.