Question

In the laboratory a student finds that it takes 24.3 joules to increase the temperature of 14.4 grams of solid tungsten from 21.7 to 35.1 degrees celsius.

The specific heat of helium calculated from her data is ______ J/g°C.

Answer 1

The specific heat of tungsten, calculated from the student's data, is 0.126 J/g°C, which is determined using the heat equation q = mc∆T and the given values for mass, heat energy, and change in temperature.

The student is asking about the specific heat of a substance, which is a concept in Chemistry.

Calculation of Specific Heat

To calculate the specific heat (c) of tungsten, the heat equation is used: q = mc∆T, where:

q is the heat energy in joules (J)

m is the mass in grams (g)

∆T is the change in temperature in degrees Celsius (°C)

From the problem:

q = 24.3 J

m = 14.4 g

∆T = 35.1°C - 21.7°C = 13.4°C

Plugging these values into the equation:

c = q / (m∆T)

c = 24.3 J / (14.4 g × 13.4 °C)

c = 24.3 J / (193.44 g°C)

c = 0.126 J/g°C

Therefore, the specific heat of tungsten calculated from her data is 0.126 J/g°C.