If one wanted to solve the equation below using the quadratic formula, what would be the b value used to substitute into the quadratic equation. 2x 2 + 9 = -6x

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asked Apr 25, 2024 43.1k views

1 Answer

DLende · Answer 1 · 2024-04-30T18:57:06+0000

The b value to be used in the quadratic formula for the equation 2x^2 + 9 = -6x is 6, after rearranging it into standard form as 2x^2 + 6x + 9 = 0.

To solve the equation 2x^2 + 9 = -6x using the quadratic formula,

we first need to rearrange the equation into standard quadratic form, which is ax^2 + bx + c = 0.

To do this, move the -6x term to the left side of the equation to get 2x^2 + 6x + 9 = 0.

Now, we can identify the coefficients for the quadratic formula.

Here, a = 2, b = 6, and c = 9.

Therefore, the value of b that you will use in the quadratic formula is 6.