The work done to move 2 mC of charge from point A to point B, each with an electric potential of +9 V, is 1.8 x 10^-2 Joules, calculated using W = Q x V.
The work done (W) in moving a charge (Q) across an electric potential difference (V) is given by the formula W = Q x V. In this case, the charge (Q) is 2 mC (milliCoulombs) and the potential difference (V) between points A and B is +9 V.
First, convert the charge from milliCoulombs to Coulombs: Q = 2 milliCoulombs = 2 x 10^-3 Coulombs.
Now, use the formula W = Q x V: W = (2 x 10^-3 Coulombs) x (9 V).
Calculate the result: W = 1.8 x 10^-2 Joules.
So, the work required to move 2 mC of charge from point A to point B is 1.8 x 10^-2 Joules.
The question probable may be:
Points A and B each have an electric potential of +9 V. How much work is required to take 2 mC of charge from A to B?