The permeability of the iron core in the solenoid is 3.26 x 10^-2 T/A.
The question asks to calculate the permeability of the iron core of a solenoid at high field strength. Given that the solenoid is 46 cm long and 2.2 cm in diameter, with 590 turns of wire, and a magnetic field of 1.9 T is produced when 42 A flows through the wire, we can determine the permeability using the formula:
The permeability of a material describes its ability to conduct magnetic fields. In this case, we are looking for the permeability of the iron core in the solenoid. The formula to calculate permeability is given by:
Permeability = Magnetic Field Strength / (Number of Turns per Unit Length * Current)
Plugging in the given values, we have:
Permeability = 1.9 T / (590 turns / (0.46 m)) * 42 A
Simplifying the equation, we find that the permeability at this high field strength is 3.26 x 10-2 T/A.
The question probable may be:
An iron-core solenoid is 46 cm long and 2.2 cm in diameter, and has 590 turns of wire. the magnetic field inside the solenoid is 1.9 t when 42 a flows in the wire. What would be the permeability at this high field strength?