The Leaning Tower of Pisa is in stable equilibrium and can lean further up to an angle of 53.1 degrees before becoming unstable.
Step-by-step explanation:
The Leaning Tower of Pisa is in a stable equilibrium because the center of gravity of the tower lies within its base of support. To determine if the tower can lean any further before becoming unstable, we need to consider the maximum angle at which it can lean without the center of gravity being outside the base.
The maximum angle can be calculated using the formula tan(theta) = h/r, where theta is the angle of inclination, h is the height off center, and r is the radius of the tower's base.
In this case, h = 4.5m and r = 3.5m (since the diameter is 7m). Plugging these values into the formula, we have tan(theta) = 4.5/3.5 ≈ 1.29. Solving for theta, we find that the maximum angle of inclination is approximately 53.1 degrees.
Therefore, the tower can lean further up to an angle of 53.1 degrees before it becomes unstable.
The probable question can be: The Leaning Tower of Pisa is 55m tall and about 7.0m in diameter. the top is 4.5m off center. Is the tower in stable equilibrium? If so, how much farther can it lean before it becomes unstable? Assume the tower is of uniform composition.