Question

light is made up of individual photons, each with a certain energy depending on the wavelength. what is the relationship between the energy of an individual photon and the wavelength of that light? write your answer in terms of , (for ), and lambda for as needed. what is the direction of the force exerted by the e-field on the charge when the pulse passes through the location of the charge?

Answer 1

The energy of photons (E) is inversely proportional to their wavelength (λ) through the equation
`\( E = (hc)/(\lambda) \)`, where h is Planck's constant and c is the speed of light. In the presence of an electric field, the force F exerted on a charge q follows Coulomb's law and is in the direction of the electric field.

The energy of individual photons in light is related to their wavelength through the energy-wavelength relationship, which is given by Planck's equation:

`\[ E = (hc)/(\lambda) \]`

where:

- E is the energy of the photon,

- h is Planck's constant
`(\(6.626 * 10^(-34)\) J·s)`,

- c is the speed of light
`(\(3.00 * 10^8\) m/s)`,

-
`\( \lambda \)` is the wavelength of the light.

This equation shows that the energy of a photon is inversely proportional to its wavelength. As the wavelength increases, the energy of the photon decreases, and vice versa.

Regarding the electric field and a charge interacting with light, when a light pulse passes through the location of a charge, the electric field exerts a force on the charge according to the direction of the field. The force F experienced by a charged particle in an electric field E is given by Coulomb's law:

`\[ F = qE \]`

where:

- F is the force,

- q is the charge of the particle,

- E is the electric field.

The force F is in the direction of the electric field E. If the charge is positive, the force is in the direction of the electric field. If the charge is negative, the force is opposite to the direction of the electric field. This relationship holds for classical electromagnetism, and it's based on the interaction of charges with electric fields.




The probable question can be: How does the energy of individual photons in light relate to their wavelength? Express your answer in terms of energy (E), Planck's constant (h), speed of light (c), and wavelength (λ). Additionally, when a light pulse passes through the location of a charge, what is the direction of the force exerted by the electric field on the charge?