110k views
3 votes
Mass of 5 kg is resting on a frictionless rt. it is connected to a cable that passes over a pulley of radius 2 cm which is then attached to a second hanging mass. the system is moving at a constant velocity

calculate the mass of the hanging block

User Aarkan
by
8.1k points

1 Answer

3 votes

Final answer:

The tension in the cable is equal to the weight of the hanging mass. Since the system is moving at a constant velocity, this tension matches the weight of the 5 kg mass on the table, which leads to the conclusion that the mass of the hanging block is also 5 kg.

Step-by-step explanation:

Given that the system is moving at a constant velocity, this indicates that the forces on the system are balanced. In the case of the 5 kg mass on a frictionless table connected to a cable and a hanging mass, the tension in the cable is equal to the weight of the hanging mass, as there is no acceleration (Newton's first law).

If we let m represent the mass of the hanging block and using the earth’s gravitational acceleration (g = 9.8 m/s²), the tension T in the rope will equal the weight of the hanging mass, which is m*g.

Since the system is moving at a constant velocity, the tension is also equal to the weight of the 5 kg mass on the table, which is 5 kg * 9.8 m/s².

Therefore, we have the equation m*g = 5 kg * 9.8 m/s².

To find the mass of the hanging block, we rearrange the equation to solve for m: m = (5 kg * 9.8 m/s²) / 9.8 m/s².

This simplifies to m = 5 kg.

Therefore, the mass of the hanging block must also be 5 kg.

User BenMorganIO
by
7.3k points