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A nationwide poll of 1250 likely voters by the Public Policy Polling group indicated that 48.2% are in favor of passing Amendment 1 to the North Carolina State Constitution. Find a 95% confidence interval for the proportion of all likely votes that would vote in favor of Amendment 1. Interpret this interval.

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Final answer:

A 95% confidence interval for the proportion of likely voters in favor of Amendment 1 is calculated using the sample proportion and sample size, resulting in an interval of approximately (45.47%, 50.93%). This interval suggests that there is a 95% probability that the true proportion lies within this range.

Step-by-step explanation:

To calculate a 95% confidence interval for the proportion of likely voters that would vote in favor of Amendment 1, we can use the formula for a confidence interval for a population proportion:

CI = p ± z * √(p(1-p)/n)

Where:

  • p = sample proportion (48.2% or 0.482)
  • z = z-score associated with a 95% confidence level (approximately 1.96)
  • n = sample size (1250)

Plugging in the values, we get:

CI = 0.482 ± 1.96 * √(0.482(1-0.482)/1250)

Calculating the margin of error:

ME = 1.96 * √(0.482*0.518/1250)

ME ≈ 1.96 * √(0.0001935096)

ME ≈ 1.96 * 0.0139141

ME ≈ 0.02730 (rounded to five decimal places)

Now we calculate the interval:

Lower bound = p - ME

Lower bound = 0.482 - 0.02730

Lower bound ≈ 0.4547

Upper bound = p + ME

Upper bound = 0.482 + 0.02730

Upper bound ≈ 0.5093

Therefore, the 95% confidence interval is approximately (0.4547, 0.5093). This interval can be interpreted to mean that we are 95% confident that the true proportion of all likely voters who would vote in favor of Amendment 1 is between 45.47% and 50.93%.

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