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Find the equation of the line below

Find the equation of the line below-example-1
User Jack Allan
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Answer:

Choose any two points from the graph.

(0, 1) ; (3, -1)

  • Using these points find the slope of the line.


\sf \boxed{\bf Slope = (y_2-y_1)/(x_2-x_1)}


\sf = (-1-1)/(3-0)\\\\\\=(-2)/(3)

  • Equation of the line in slope y-intercept form: y =mx + b

Here, m is the slope and b is the y-intercept. substitute m value in the above equation.


y = (-2)/(3)x + b

  • The point (0,1) passes through the line. Substitute x =0 and y = 1 in the above equation and find the value of y-intercept.


\sf 1 = 0 +b\\b = 1

  • Equation of the line:


\boxed{\bf y =(-2)/(3)x+1}

User Zaquest
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