Question

Find the slope of a line perpendicular to the line containing the points (12, -8) and (5, -4).

Answer 1

`(7)/(4)`

Explanation:

Find the slope of the line containing points (12, -8) & (5 , -4)

`\boxed{\bf Slope =(y_2-y_1)/(x_2-x_1)}`

`\sf = (-4-(-8))/(5-12)\\\\\\=(-4+8)/(-7)\\\\\\=(4)/(-7)\\\\\\m=(-4)/(7)`

`\text{Slope of the line perpendicular to the given line}= (-1)/(m)`

`\sf = -1 / (-4)/(7)\\\\\\= -1 * (-7)/(4)\\\\\\=(7)/(4)`