Final answer:
the number of oxygen atoms in a 100g sample of vanadium(V) oxide is 1.653 x 10^24 oxygen atoms.
Step-by-step explanation:
To calculate the number of oxygen atoms in a 100g sample of vanadium(V) oxide, you first need to know the chemical formula of vanadium(V) oxide, which is V2O5. This means there are 5 moles of oxygen for every 2 moles of vanadium.
The molar mass of V2O5 can be calculated by adding the molar masses of 2 vanadium atoms and 5 oxygen atoms. The molar masses are approximately 51 g/mol for vanadium and 16 g/mol for oxygen, giving us a molar mass for V2O5 of (2*51) + (5*16) = 182 g/mol.
Next, we find the moles of V2O5 in a 100g sample by dividing the mass by the molar mass:
100 g V2O5 / 182 g/mol = 0.549 moles of V2O5
Since there are 5 oxygen atoms per V2O5 molecule, we multiply the moles of V2O5 by 5 to get the moles of oxygen atoms:
0.549 moles V2O5 * 5 = 2.747 moles of oxygen atoms
Finally, convert moles of oxygen atoms to the actual number of oxygen atoms using Avogadro's number (6.022 x 10^23 atoms/mol):
2.747 moles O * 6.022 x 10^23 atoms/mol = 1.653 x 10^24 oxygen atoms