224k views
5 votes
The sum of two quantities is y, one of the quantities varies directly as x ² and the other inversely as x.If y=32, when x=2 , and y=86 , when x=4, find

A. An equation for y in terms of x.

B. The value of y when x is 3

1 Answer

6 votes

Final answer:

To find the equation for y in terms of x, two systems of equations are solved to find the constants a and b. The resulting equation is y = 5x² + 32/x. Using this equation, the value of y when x is 3 is approximately 55.67.

Step-by-step explanation:

Finding the Equation and Value of y in terms of x

We are given that y is the sum of two quantities: one that varies directly as x² and one that varies inversely as x. This can be expressed as:

y = ax² + b/x where a and b are constants.

First, we'll plug in the given values to find the constants:

We can solve these equations simultaneously to find the values of a and b.

Multiplying the first equation by 2 to eliminate the fraction, we get:

We'll multiply the second equation by 4 to align the b terms:

Subtracting the first from the second gives us:

Solving for a gives a = 5 and substituting a back into any of the initial equations gives us b = 32.

The equation for y is:

y = 5x² + 32/x

To find the value of y when x=3, we substitute 3 into our equation for x:

y = 5(3²) + 32/3

y = 45 + 32/3

y = 45 + 10.67

y ≈ 55.67

Therefore, when x is 3, y is approximately 55.67.

User Zzlalani
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories