172k views
4 votes
Someone please help due soon.

Someone please help due soon.-example-1
User Fredster
by
7.6k points

1 Answer

2 votes

The analysis of the equations indicates that we get;

Part A; (c) y = 4·(x - 3)²

Part B; (A) Minimum

Part C; (3, 0)

The steps used to obtain the correct equation, and the minimum point are as follows;

Part A

The maximum or minimum of a function is the vertex of the function.

The vertex form of a quadratic equation is; f(x) = a·(x - h)² + k

Where; (h, k) represents the coordinates of the vertex of the quadratic equation

a represents the stretch of the function and the reflection across x-axis

Comparing the specified equations, the equation that best approximates the vertex for of the quadratic equation is the option (c) y = 4·(x - 3)²

Therefore, the equation that reveals the maximum or minimum is the option (c) y = 4·(x - 3)²

Part B;

The value in the equation y = 4·(x - 3)² corresponding to the value a in the vertex form of the equation of a quadratic equation f(x) = a·(x - h)² + k is a = 4, which indicates that the leading coefficient of the equation is positive, corresponding to a parabola that opens up, having a minimum point; Therefore, the equation has a minimum

Part C;

The coordinates of the minimum point of the equation y = 4·(x - 3)², obtained by comparing the equation to the vertex form of a quadratic equation f(x) = a·(x - h)² + k, with a vertex of (h, k), where h = 3, and k = 0 is (h, k) = (3, 0)

The vertex is (3, 0)

User KingJackaL
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories