Question

Solve the equation below for p -1/2(p+2)=-3-p

Answer 1

p = -4

Explanation:

Let's solve the equation for
`\sf p`:

`\sf -(1)/(2)(p + 2) = -3 - p`

First, distribute the
`\sf -(1)/(2)` on the left side:

`\sf -(1)/(2)p - (2)/(2) = -3 - p`

`\sf -(1)/(2)p - 1= -3 - p`

Now, combine like terms on both sides of the equation:

Add
`\sf p` to both sides:

`\sf -(1)/(2)p + p - 1 = -3`

Combine
`\sf -(1)/(2)p + p`:

`\sf (-1+2)/(2)p - 1 = -3`

`\sf (1)/(2)p - 1 = -3`

Now, add 1 to both sides to isolate
`\sf (1)/(2)p`:

`\sf (1)/(2)p = -3+1`

`\sf (1)/(2)p = -2`

Multiply both sides by 2 to solve for
`\sf p`:

`\sf p = -4`

So, the solution to the equation is
`\sf p = -4`.

Answer 2

p=4

Explanation:

-1/2(p+2)=-3 -p

multiply by negative two

1(p+2)=6+2p

Simplify

p+2=6+2p

Subtract p

2=6+p

subtract 6

p=4